Let us consider the nominal mix is 1:2:4

The output of mix is considered as 67%

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To achieve 1 cum output, we need 1/0.67 = 1.49 say 1.50 cum dry mix.

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Now add the wastage of 2%, i.e (1.50 + 0.02) = 1.52 cum.

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Volume of cement = (cement/cement+sand+aggregate) × Total material

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=(1/1+2+4) × 1.52 =0.2171 cum

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As we know, the density of cement is 1440 kg/cum and Weight of 1 bag cement = 50 kg.

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Therefore volume of 1 bag cement = 50/1440 =0.0347 cum.

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∴ No. of cement bags required in 1 cubic meter = 0.2171/0.0347 = 6.25 bags.

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∴ No. of cement bags required in 1 cubic meter = 0.2171/0.0347 = 6.25 bags.

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